5894. 至少在两个数组中出现的值

数据量才100，直接暴力

class Solution:
    def twoOutOfThree(self, nums1: List[int], nums2: List[int], nums3: List[int]) -> List[int]:
        cnt1,cnt2,cnt3=Counter(nums1),Counter(nums2),Counter(nums3)
        seq=set(nums1+nums2+nums3)
        res=[]
        for s in seq:
            if (cnt1[s]>0)+(cnt2[s]>0)+(cnt3[s]>0)>=2:
                res.append(s) 
        return res

5895. 获取单值网格的最小操作数

先转化成一维数组方便处理，找中位数

class Solution:
    def minOperations(self, grid: List[List[int]], x: int) -> int:
        seq=[i for x in grid for i in x]
        seq.sort()
        n=len(seq)
        mid=seq[n//2]
        res=0
        for s in seq:
            if (mid-s)%x!=0:
                return -1
            res+=abs(mid-s)//x
        return res

5896. 股票价格波动

SortedList，SortedDict，红黑树，相当于Java里的TreeSet，不属于标准库，但力扣可以使用

from sortedcontainers import SortedList,SortedDict
class StockPrice:
·
    def __init__(self):
        self.time=SortedDict()
        self.price=SortedList()

    def update(self, timestamp: int, price: int) -> None:
        if timestamp in self.time:
            tmp=self.time[timestamp]
            self.price.discard(tmp)
        self.time[timestamp]=price
        self.price.add(price)

    def current(self) -> int:
        tmp=self.time.peekitem(-1)
        return tmp[-1]

    def maximum(self) -> int:
        return self.price[-1]

    def minimum(self) -> int:
        return self.price[0]


# Your StockPrice object will be instantiated and called as such:
# obj = StockPrice()
# obj.update(timestamp,price)
# param_2 = obj.current()
# param_3 = obj.maximum()
# param_4 = obj.minimum()